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How to find the work done to a train with a mass of 2.90×104 kg?

In the 1950s, an experimental train that had a mass of 2.90 x104 kg was powered across a level track by a jet engine that produced a thrust of 4.60 105 N for a distance of 509 m. Assume that air resistance is negligible.
(a) Find the work done on the train.
_______ J

(b) Find the change in kinetic energy.
_______ J

(c) Find the final kinetic energy of the train if it started from rest.
_______ J

(d) Find the final speed of the train if there had been no friction.
_______ m/s

<< Find the work done on the train. >>

Work = W = (4.6 x 10^5)(509)

W = 2.3414 x 10^8 joules

<< Find the change in kinetic energy >>

Since air resistance is negligible, the the change in kinetic energy is equal to the work done on the train = 2.3414 x 10^8 joules

<< Find the final kinetic energy of the train if it started from rest >>

Same answer as above.

Final KE of train = 2.3414 x 10^8 joules

<< Find the final speed of the train if there had been no friction. >>

KE = (1/2)mV^2

where

m = mass of the train = 2.90 x 10^4 kg.
V = train velocity

Substituting values,

2.3414 x 10^8 = (1/2)(2.90 x 10^4)V^2

V^2 = 1.615 x 10^4

V = 127.1 m/sec.

Hope this helps.



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